Question:medium

Wolff–Kishner reduction\(\xrightarrow{NH_2-NH_2/KOH}\;\; Product\)

Updated On: Feb 25, 2026
  • Alcohol
  • Alkane
  • Alkene
  • Ester
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The Correct Option is B

Solution and Explanation

The Wolff–Kishner reduction is a chemical reaction used to reduce ketones and aldehydes to alkanes. In this reaction, the carbonyl group (\(C=O\)) of a ketone or aldehyde is converted into a methylene group (\(CH_2\)). This is achieved using hydrazine (\(NH_2-NH_2\)) and a strong base such as \(KOH\). 

  1. When the given compound, which is a ketone, undergoes Wolff–Kishner reduction, the carbonyl group is first reacted with hydrazine to form a hydrazone intermediate.
  2. Under basic conditions with \(KOH\), the hydrazone is further decomposed to produce an alkane and release nitrogen gas (\(N_2\)).

The given reaction can be represented as follows:

 +\(NH_2-NH_2\)\(\xrightarrow{KOH}\)Alkane+\(N_2\)

Conclusion: The Wolff–Kishner reduction converts the ketone in the given compound to an alkane. Therefore, the correct answer is Alkane.

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