Question

\(\xrightarrow{NH_2-NH_2/KOH}\;\; Product\)

• A. Alcohol
• B. Alkane
• C. Alkene
• D. Ester

Answer 1

The Correct Option is B

The Wolff–Kishner reduction is a chemical reaction used to reduce ketones and aldehydes to alkanes. In this reaction, the carbonyl group (\(C=O\)) of a ketone or aldehyde is converted into a methylene group (\(CH_2\)). This is achieved using hydrazine (\(NH_2-NH_2\)) and a strong base such as \(KOH\). 

1. When the given compound, which is a ketone, undergoes Wolff–Kishner reduction, the carbonyl group is first reacted with hydrazine to form a hydrazone intermediate.
2. Under basic conditions with \(KOH\), the hydrazone is further decomposed to produce an alkane and release nitrogen gas (\(N_2\)).

The given reaction can be represented as follows:

+

\(NH_2-NH_2\)

\(\xrightarrow{KOH}\)

Alkane

+

\(N_2\)

Conclusion: The Wolff–Kishner reduction converts the ketone in the given compound to an alkane. Therefore, the correct answer is Alkane.