The correct stability order of carbocations is
- $(\text{CH}_3)_3\text{C}^+ > \text{CH}_3 - \text{CH}_2 > (\text{CH}_3)_2\text{CH}^+ > \text{CH}_3 \\$
The Correct Option is B
Solution and Explanation
Carbocation Stability Order: The following sequence represents the correct order of carbocation stability:
(CH3)3C+ > (CH3)2CH+ > CH3–CH2+ > CH3+.
This establishes the definitive stability ranking for the provided carbocations as:
(CH3)3C+ > (CH3)2CH+ > CH3–CH2+ > CH3+.
Top Questions on carbonyl compounds
- The statements that are incorrect about the nickel(II) complex of dimethylglyoxime are :
A. It is red in colour.
B. It has a high solubility in water at pH = 9.
C. The Ni ion has two unpaired d-electrons.
D. The N – Ni – N bond angle is almost close to 90°.
E. The complex contains four five-membered metallacycles (metal containing rings).
Choose the correct answer from the options given below :- JEE Main - 2026
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Given below are the four isomeric compounds \(P, Q, R, S\):
\(P\): Aromatic compound containing an \(-\mathrm{OH}\) group
\(Q\): Aromatic compound containing an \(-\mathrm{CHO}\) group (aldehyde)
\(R\): Aromatic compound containing a ketone group
\(S\): Aromatic compound containing a ketone group Identify the correct statements from below:
[A.] \(Q, R\) and \(S\) will give precipitate with \(2,4\)-DNP.
[B.] \(P\) and \(Q\) will give positive Baeyer’s test.
[C.] \(Q\) and \(R\) will give sooty flame.
[D.] \(R\) and \(S\) will give yellow precipitate with \(I_2/\mathrm{NaOH}\).
[E.] \(Q\) alone will deposit silver with Tollens’ reagent. Choose the correct option.- JEE Main - 2026
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Match the LIST-I with LIST-II
Choose the correct answer from the options given below:- JEE Main - 2026
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- Which of the following is the correct order with respect to the property indicated?
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- Chemistry
- carbonyl compounds
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