Step 1: Magnetic Field Distribution Analysis
Ampère's Circuital Law defines the magnetic field \( B \) around a current-carrying wire as: \[ \oint B \cdot dl = \mu_0 I_{\text{enc}} \] Here, \( I_{\text{enc}} \) represents the current encompassed by the selected circular Amperian loop.
Step 2: Magnetic Field Within the Wire (\( r<a \))
Assuming uniform current distribution, the enclosed current at radius \( r \) (\( r<a \)) is calculated as: \[ I_{\text{enc}} = I \frac{\pi r^2}{\pi a^2} = I \frac{r^2}{a^2} \] Applying Ampère’s law for a circular path of radius \( r \): \[ B \cdot 2\pi r = \mu_0 I_{\text{enc}} \] Substituting \( I_{\text{enc}} \): \[ B \cdot 2\pi r = \mu_0 I \frac{r^2}{a^2} \] Resulting in: \[ B = \frac{\mu_0 I r}{2\pi a^2} \] This indicates that the magnetic field inside the wire is directly proportional to \( r \).
Step 3: Magnetic Field Exterior to the Wire (\( r>a \))
For \( r>a \), the Amperian loop encloses the total current \( I \): \[ B \cdot 2\pi r = \mu_0 I \] Yielding: \[ B = \frac{\mu_0 I}{2\pi r} \] Consequently, the magnetic field outside the wire is inversely proportional to \( r \).Final Answer:
The magnetic field exhibits direct proportionality to \( r \) inside the wire and inverse proportionality to \( r \) outside the wire.