Nucleophilic addition reactivity in carbonyl compounds is primarily governed by two factors: electron withdrawal and steric hindrance. Electron-withdrawing substituents enhance reactivity by increasing the carbonyl carbon's electrophilicity, whereas steric bulk diminishes it. The following compounds were examined:
| Compound | Factors Influencing Reactivity |
|---|---|
| Acetophenone | The presence of an electron-donating alkyl group reduces the carbonyl carbon's electrophilicity, thus lowering reactivity. |
| p-Tolualdehyde | A methyl group on the benzene ring exhibits a slight electron-donating effect, resulting in lower reactivity than benzaldehyde but higher than acetophenone. |
| Benzaldehyde | In the absence of additional electron-donating groups, it is more reactive than acetophenone and p-tolualdehyde, but less reactive than p-nitrobenzaldehyde. |
| p-Nitrobenzaldehyde | The nitro group acts as a potent electron-withdrawing substituent, leading to the highest increase in the carbonyl carbon's reactivity. |
Consequently, the compounds exhibit an increasing order of reactivity towards nucleophilic addition reactions as follows:
Acetophenone < p-Tolualdehyde < Benzaldehyde < p-Nitrobenzaldehyde.
Given below are the four isomeric compounds \(P, Q, R, S\): 
\(P\): Aromatic compound containing an \(-\mathrm{OH}\) group
\(Q\): Aromatic compound containing an \(-\mathrm{CHO}\) group (aldehyde)
\(R\): Aromatic compound containing a ketone group
\(S\): Aromatic compound containing a ketone group Identify the correct statements from below:
[A.] \(Q, R\) and \(S\) will give precipitate with \(2,4\)-DNP.
[B.] \(P\) and \(Q\) will give positive Baeyer’s test.
[C.] \(Q\) and \(R\) will give sooty flame.
[D.] \(R\) and \(S\) will give yellow precipitate with \(I_2/\mathrm{NaOH}\).
[E.] \(Q\) alone will deposit silver with Tollens’ reagent. Choose the correct option.
Match the LIST-I with LIST-II 
Choose the correct answer from the options given below: