HCO+
CO+
Benzaldehyde is synthesized from benzene using the Gattermann-Koch reaction, an electrophilic aromatic substitution. This process requires generating an electrophile that then reacts with the benzene ring. To determine the correct electrophile, consider the following options:
In the Gattermann-Koch reaction, the electrophile is produced when carbon monoxide (CO) interacts with hydrochloric acid (HCl) in the presence of a Lewis acid catalyst, typically anhydrous aluminum chloride (AlCl3). This interaction forms the formyl cation (HCO+), which subsequently functions as the electrophile, reacting with benzene to yield benzaldehyde.
Consequently, the specific electrophile participating in the Gattermann-Koch reaction is: HCO+.
Given below are the four isomeric compounds \(P, Q, R, S\): 
\(P\): Aromatic compound containing an \(-\mathrm{OH}\) group
\(Q\): Aromatic compound containing an \(-\mathrm{CHO}\) group (aldehyde)
\(R\): Aromatic compound containing a ketone group
\(S\): Aromatic compound containing a ketone group Identify the correct statements from below:
[A.] \(Q, R\) and \(S\) will give precipitate with \(2,4\)-DNP.
[B.] \(P\) and \(Q\) will give positive Baeyer’s test.
[C.] \(Q\) and \(R\) will give sooty flame.
[D.] \(R\) and \(S\) will give yellow precipitate with \(I_2/\mathrm{NaOH}\).
[E.] \(Q\) alone will deposit silver with Tollens’ reagent. Choose the correct option.
Match the LIST-I with LIST-II 
Choose the correct answer from the options given below: