Question:medium

DIRECTIONS for questions 45 and 46: Read the information below and answer the question that follows.
It is possible to arrange eight of the nine numbers 2, 3, 4, 5, 7, 10, 11, 12, 13 in the vacant squares of the 3 by 4 array shown below so that the arithmetic average of the numbers in each row and column is the same integer.
115
9
14

46. Which one of the nine numbers must be left out when completing the array?

Show Hint

Find which single number, once removed from the sum of all thirteen entries in the grid, leaves a total divisible by 12.
Updated On: Jul 13, 2026
  • 4
  • 5
  • 7
  • 10
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Reduce the problem using remainders mod 12.
Since the grid total must be a multiple of 12 (from the row/column average condition, grid total = $12x$), look at the sum of all thirteen numbers modulo 12 instead of testing every candidate one by one.
\[ 1+2+3+4+5+7+9+10+11+12+13+14+15=106 \]
$106 = 8\times12 + 10$, so $106 \equiv 10 \pmod{12}$.

Step 2: Match the remainder to the number that must be dropped.
Removing one number from the total must bring the remainder down to 0 mod 12, since a valid grid total has to be an exact multiple of 12. That means the number removed must itself leave a remainder of 10 when divided by 12.

Step 3: Check which of the nine free numbers fits.
Among 2, 3, 4, 5, 7, 10, 11, 12, 13, only the number 10 leaves a remainder of 10 when divided by 12 (since 10 is less than 12, its remainder is just 10 itself). None of the others, 2, 3, 4, 5, 7, 11, 12 or 13, match.

Step 4: Final Answer.
So the number 10 is the one that must be left out of the array.
\[ \boxed{10} \]
Was this answer helpful?
0


Questions Asked in XAT exam