A sub-atomic particle of mass \( 10^{-30} \) kg is moving with a velocity of \( 2.21 \times 10^6 \) m/s. Under the matter wave consideration, the particle will behave closely like (h = \( 6.63 \times 10^{-34} \) J.s)
The de Broglie wavelength, \(\lambda\), describes the behavior of a sub-atomic particle as a matter wave. It is calculated using the formula: \(\lambda = \frac{h}{mv}\)
The variables are defined as:
Substituting these values yields:
\(\lambda = \frac{6.63 \times 10^{-34}}{10^{-30} \times 2.21 \times 10^6}\)
The calculation results in:
\(\lambda = \frac{6.63 \times 10^{-34}}{2.21 \times 10^{-24}}\)
\(\lambda \approx 3.00 \times 10^{-10}\) meters, equivalent to 0.3 nanometers.
This calculated wavelength falls within the typical range of X-rays (0.01 to 10 nanometers). Therefore, when considered as a matter wave, the particle exhibits behavior similar to X-rays.
Conclusion: Under matter wave consideration, the particle's behavior is analogous to that of X-rays.