For a closed organ pipe, the relationship between pipe length \( L \) and harmonic number \( n \) is \( L = \frac{(2n-1)\lambda}{4} \), where \( \lambda \) is the sound's wavelength. For the third overtone, \( n = 4 \). This corresponds to the 4th harmonic, characterized by 4 nodes and 4 antinodes. The oscillation pattern consists of four full loops and one half loop, resulting in 4 nodes and 4 antinodes.
Final Answer:
\[
\boxed{\text{Four nodes and four antinodes}}.
\]