Question:medium

The speed of a wave is \( 30 \, \mathrm{m/s} \). If the distance between 11 crests is \( 1 \, \mathrm{m} \), what is the frequency (in Hz)?

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Updated On: Nov 26, 2025
  • \( 300 \, \mathrm{Hz} \)
  • \( 330 \, \mathrm{Hz} \)
  • \( 350 \, \mathrm{Hz} \)
  • \( 360 \, \mathrm{Hz} \)
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The Correct Option is A

Solution and Explanation

The wavelength (\( \lambda \)) of a wave is the spatial period between successive identical points, such as crests. For 11 crests, the total distance spans 10 wavelengths:\[10 \lambda = 1 \, \mathrm{m}.\]Consequently, the wavelength is calculated as:\[\lambda = \frac{1}{10} = 0.1 \, \mathrm{m}.\]The wave frequency (\( f \)) is determined by the equation:\[f = \frac{v}{\lambda},\]where: \( v = 30 \, \mathrm{m/s} \) represents the wave speed, \( \lambda = 0.1 \, \mathrm{m} \) is the wavelength.Substituting these values yields:\[f = \frac{30}{0.1} = 300 \, \mathrm{Hz}.\]Therefore, the wave's frequency is \( \mathbf{300 \, \mathrm{Hz}} \).
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