Question:easy

When a triangular waveform is applied as an input to a differentiator, the output is

Show Hint

To remember differentiation vs. integration for waves: - Differentiating a Triangular wave gives a Square wave. - Integrating a Square wave gives a Triangular wave. - Differentiating a Square wave gives Spikes (impulses).
Updated On: Jul 1, 2026
  • A DC line
  • An inverted triangular waveform
  • Square waveform
  • The first harmonic of the triangular wave
Show Solution

The Correct Option is C

Solution and Explanation

1. Analyzing the Triangular Waveform: A triangular wave consists of linear voltage ramps. It has a constant positive slope during its rising edge and a constant negative slope during its falling edge.

Rising Edge: The slope ($m = \frac{dV}{dt}$) is a positive constant value.

Falling Edge: The slope ($m = \frac{dV}{dt}$) is a negative constant value.

2. Effect of Differentiation: When these constant slopes are differentiated:

• The derivative of a constant positive slope results in a

constant positive voltage level.

• The derivative of a constant negative slope results in a

constant negative voltage level.

3. Resulting Output: The output switches abruptly between a fixed positive level and a fixed negative level at the peaks of the triangular wave. This geometric pattern is the definition of a

square waveform (or a rectangular waveform if the duty cycle is not 50%). Note: If the differentiator is an inverting Op-Amp type, the output will be a square wave that is $180^\circ$ out of phase with the slopes (negative voltage for positive slope), but it remains a square waveform.
Was this answer helpful?
0