Question:medium

Co-factor of -4 in $\begin{vmatrix} 1 & 2 & 3 \\ -4 & 3 & 6 \\ 2 & -7 & 9 \end{vmatrix}$ is

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You can quickly determine the sign using a checkerboard pattern: $\begin{vmatrix} + & - & + \\ - & + & - \\ + & - & + \end{vmatrix}$. Since -4 is in a "minus" position, its co-factor will be the negative of its minor.
Updated On: Jul 1, 2026
  • $3$
  • $11$
  • $39$
  • $-39$
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The Correct Option is D

Solution and Explanation

Step 1: Identify the position and sign: The element -4 is located in the second row ($i=2$) and the first column ($j=1$). The formula for a co-factor $C_{ij}$ is: $$C_{ij} = (-1)^{i+j} \cdot M_{ij}$$ Where $M_{ij}$ is the minor of the element. For our position (2,1): $$\text{Sign} = (-1)^{2+1} = (-1)^3 = -1$$

Step 2: Find the Minor ($M_{21}$): The minor is found by deleting the row and column containing -4 (the 2nd row and 1st column). The remaining elements form a $2 \times 2$ determinant: $$M_{21} = \begin{vmatrix} 2 & 3 \\ -7 & 9 \end{vmatrix}$$ Calculating the value: $$M_{21} = (2 \times 9) - (3 \times -7)$$ $$M_{21} = 18 - (-21) = 18 + 21 = 39$$

Step 3: Calculate the Co-factor: Combine the sign and the minor: $$C_{21} = (-1) \times 39 = -39$$ Thus, the co-factor of -4 in the given determinant is -39.
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