To determine the minimum count of Blue beads in any valid arrangement on a 5x5 grid (25 cells), the following rules must be applied. Each cell contains a Red, Blue, or Green bead.
Minimizing Blue beads requires maximizing Red and Green beads within these constraints. Analysis shows:
Considering a row or column structure:
Applying these rules:
Through logical pattern construction and minimal compliant configurations, it is determined that at least six Blue beads are required to satisfy all constraints across the grid.
| R | G | B | G | R |
| G | B | G | R | G |
| B | G | R | G | B |
| G | R | G | B | G |
| R | G | B | G | R |
This configuration, with strategically placed Blue beads, meets all conditions minimally, establishing the requirement of at least 6 Blue beads. Therefore, the minimum number of Blue beads in any valid configuration is 6.
| Ullas | Vasu | Waman | Xavier | Yusuf | |
|---|---|---|---|---|---|
| Mean rating | 2.2 | 3.8 | 3.4 | 3.6 | 2.6 |
| Median rating | 2 | 4 | 4 | 4 | 3 |
| Model rating | 2 | 4 | 5 | 5 | 1 and 4 |
| Range of rating | 3 | 3 | 4 | 4 | 3 |
| Firm | First year of existence | Last year of existence | Total amount raised (Rs. crores) |
|---|---|---|---|
| Alfloo | 2009 | 2016 | 21 |
| Bzygoo | 2012 | 2015 | |
| Czechy | 2013 | 9 | |
| Drjbna | 2011 | 2015 | 10 |
| Elavalaki | 2010 | 13 |
| Table 1: 2-day averages for Days through 5 | |||
|---|---|---|---|
| Day 2 | Day 3 | Day 4 | Day 5 |
| 15 | 15.5 | 16 | 17 |
| Table 2 : Ranks of participants on each day | |||||
|---|---|---|---|---|---|
| Day 1 | Day 2 | Day 3 | Day 4 | Day 5 | |
| Akhil | 1 | 2 | 2 | 3 | 3 |
| Bimal | 2 | 3 | 2 | 1 | 1 |
| Chatur | 3 | 1 | 1 | 2 | 2 |
| Firm | First year of existence | Last year of existence | Total amount raised (Rs. crores) |
|---|---|---|---|
| Alfloo | 2009 | 2016 | 21 |
| Bzygoo | 2012 | 2015 | |
| Czechy | 2013 | 9 | |
| Drjbna | 2011 | 2015 | 10 |
| Elavalaki | 2010 | 13 |