45%
47%
42 %
49%
Let the initial selling price of items \(A\) and \(B\) be \(p\). She profited 20% on \(A\). This implies \(1.2 \times c = p\), so the cost of \(A\) is \(c = \frac{5p}{6}\). She incurred a 10% loss on \(B\). This implies \(0.9 \times c = p\), so the cost of \(B\) is \(c = \frac{10p}{9}\). She then sold both items at a price that yielded a 10% profit on \(B\). The selling price for \(B\) became \(\frac{11}{10} \times \frac{10p}{9} = \frac{11p}{9}\). The profit percentage on \(A\) is calculated as \(\frac{\frac{11p}{9}-\frac{5p}{6}}{\frac{5p}{6}} \times 100\). Simplifying this yields \(46.66\%\), which is approximately \(47\%\). Therefore, the correct option is (B): \(47\%\).