Question:medium

Twenty five coloured beads are to be arranged in a grid comprising of five rows and five columns. Each cell in the grid must contain exactly one bead. Each bead is coloured either Red, Blue or Green.
While arranging the beads along any of the five rows or along any of the five columns, the rules given below are to be followed:
(1) Two adjacent beads along the same row or column are always of different colours.
(2) There is at least one Green bead between any two Blue beads along the same row or column.
(3) There is at least one Blue and at least one Green bead between any two Red beads along the same row or column.
Every unique, complete arrangement of twenty five beads is called a configuration.
Two Red beads have been placed in ‘second row, third column’ and ‘third row, second column’.
How many more Red beads can be placed so as to maximise the number of Red beads used in the configuration?
[This Question was asked as TITA]

Updated On: Jan 15, 2026
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The Correct Option is A

Solution and Explanation

To address the problem of arranging colored beads according to specified rules while maximizing the count of Red beads, a systematic approach is required:
(1) Rule 1 dictates that adjacent beads must differ in color, imposing a checkerboard constraint on both rows and columns.
(2) Rule 2 mandates at least one Green bead between any two Blue beads, maintaining an alternation requirement.
(3) Rule 3 requires at least one Blue bead and one Green bead between any two Red beads, increasing color diversity.
The initial bead placements are Red at 'second row, third column' and 'third row, second column'. The following represents one optimal configuration for placing additional Red beads within these constraints:

GBRBG
BRGRB
RGGGB
BRBRG
GBGBR

In this configuration:

  • Both initial Red beads satisfy all rules. Additional Red beads are strategically placed at positions (2,4), (4,2), (4,4), and (5,5) to maximize the total count while adhering to constraints.
  • The entire grid remains compliant with all rules, ensuring Red beads alternate with both Blue and Green beads as required.
  • The total count of Red beads is 8: the 2 initial beads plus 6 additional Red beads placed according to the rules and optimally.

Consequently, the maximum number of additional Red beads that can be placed is 6.

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