Question:medium

Three blocks $A, B$ and $C$ are lying on a smooth horizontal surface, as shown in the figure. $A$ and $B$ have equal masses, $m$ while $C$ has mass $M$. Block $A$ is given an brutal speed $v$ towards $B$ due to which it collides with $B$ perfectly inelastically. The combined mass collides with $C$, also perfectly inelastically $\frac{5}{6}$ th of the initial kinetic energy is lost in whole process. What is value of $M/m$ ?

Updated On: Mar 31, 2026
  • 4
  • 5
  • 3
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The Correct Option is A

Solution and Explanation

To find the value of $M/m$, we need to analyze the problem using the principles of conservation of momentum and kinetic energy loss in inelastic collisions.

  1. Initially, block $A$ with mass $m$ is moving with velocity $v$, and blocks $B$ and $C$ are at rest.
  2. First Collision (A and B):
    • Since the collision between $A$ and $B$ is perfectly inelastic, the two blocks stick together after the collision.
    • By conservation of momentum, the velocity $u$ of the combined mass after the collision can be given by:
    • $m \cdot v = (m + m) \cdot u \Rightarrow u = \frac{v}{2}$
  3. Second Collision (Combined mass of A & B with C):
    • Again, the collision is perfectly inelastic, so all three blocks move together as a single unit.
    • Let the final velocity of the combined mass after this collision be $V$.
    • Using conservation of momentum:
    • $(2m) \cdot \frac{v}{2} = (2m + M) \cdot V \Rightarrow v \cdot m = (2m + M) \cdot V$
    • So, $ V = \frac{v \cdot m}{2m + M} $
  4. Energy Analysis:
    • Initial kinetic energy: $ KE_{\text{initial}} = \frac{1}{2} m v^2 $
    • Final kinetic energy: $ KE_{\text{final}} = \frac{1}{2} \cdot (2m + M) \cdot V^2 $
    • Since $\frac{5}{6}$ th of the initial kinetic energy is lost, $\frac{1}{6}$ th remains:
    • $\frac{1}{2} \cdot (2m + M) \cdot \left(\frac{v \cdot m}{2m + M}\right)^2 = \frac{1}{6} \cdot \frac{1}{2} m v^2 $
    • This results in: $ (2m + M) \cdot \frac{m^2 \cdot v^2}{(2m + M)^2} = \frac{m v^2}{6} $
    • Simplifying gives: $\frac{m^2}{2m + M} = \frac{m}{6}$
    • Cross-multiplying and simplifying:
    • $6m^2 = m(2m + M)$
    • Which results in: $4m^2 = mM \; \Rightarrow \; M = 4m $
  5. Thus, the value of $M/m$ is 4, which matches the correct option.

Therefore, the correct answer is 4.

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