Question:medium

The order of the differential equation whose general solution is \[ y=a\sin x+b\cos x \] where \(a\) and \(b\) are arbitrary constants, is

Show Hint

Number of arbitrary constants in the general solution equals the order of the differential equation.
  • \(2\)
  • \(4\)
  • \(1\)
  • \(3\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
The order of a differential equation is fundamentally linked to the number of arbitrary constants in its general solution. To find the differential equation from a general solution, we must differentiate the solution enough times to be able to eliminate all the arbitrary constants.
Step 2: Key Formula or Approach:
The order of a differential equation is equal to the number of essential arbitrary constants in its general solution.
Step 3: Detailed Explanation:
The given general solution is: \[ y = a \sin x + b \cos x \] This solution contains two arbitrary constants, 'a' and 'b'. Therefore, the order of the corresponding differential equation must be 2. To verify this, we can form the differential equation: Differentiate the solution with respect to x: \[ \frac{dy}{dx} = a \cos x - b \sin x \quad \dots(1) \] Differentiate again with respect to x: \[ \frac{d^2y}{dx^2} = -a \sin x - b \cos x \quad \dots(2) \] We can see that the right-hand side of equation (2) is the negative of the original expression for y. \[ \frac{d^2y}{dx^2} = -(a \sin x + b \cos x) \] \[ \frac{d^2y}{dx^2} = -y \] Rearranging this gives the differential equation: \[ \frac{d^2y}{dx^2} + y = 0 \] This is a second-order differential equation, as predicted.
Step 4: Final Answer:
Since there are two arbitrary constants in the general solution, the order of the differential equation is 2. Therefore, option (A) is correct.
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