The differential equation \(e \, dy = (x + 1) \, dx\) requires variable separation and integration. Integrating both sides yields \[\int e \, dy = \int (x + 1) \, dx \quad \Rightarrow \quad y = (x + 1)\log(x + 1) - x + C.\]Using the initial condition \(y(0) = 3\), we find the constant of integration: \[3 = (0 + 1)\log(0 + 1) - 0 + C \quad \Rightarrow \quad C = 3.\]The particular solution is therefore: \[y = (x + 1)\log(x + 1) - x + 3.\]