Step 1: Understanding the Concept:
This question tests the property of determinants under scalar multiplication. When a matrix is multiplied by a scalar constant, its determinant is scaled by that constant raised to the power of the matrix's order (size).
Step 2: Key Formula or Approach:
For any square matrix A of order $n$ and any scalar $k$, the determinant of the matrix $kA$ is given by the formula:
\[ \det(kA) = k^n \det(A) \]
Step 3: Detailed Explanation:
We are given the following information:
The matrix A is a 2x2 matrix, so its order is $n=2$.
The determinant of A is $\det(A) = 5$.
We need to find the determinant of the matrix 2A, so the scalar is $k=2$.
Using the formula from Step 2:
\[ \det(2A) = 2^n \det(A) \]
Substitute the values of $n$ and $\det(A)$:
\[ \det(2A) = 2^2 \times 5 \]
\[ \det(2A) = 4 \times 5 \]
\[ \det(2A) = 20 \]
Step 4: Final Answer:
The determinant of the matrix 2A is 20. Therefore, option (B) is the correct answer.