The number of $sp^2$ hybrid orbitals in a molecule of benzene is :

Question

Match List - I with List - II.

List - I (Complex)	List - II (Hybridisation)
(A) $[\text{CoF}_6]^{3-}$	(I) $ d^2 sp^3 $
(B) $[\text{NiCl}_4]^{2-}$	(II) $ sp^3 $
(C) $[\text{Co(NH}_3)_6]^{3+}$	(III) $ sp^3 d^2 $
(D) $[\text{Ni(CN}_4]^{2-}$	(IV) $ dsp^2 $

Choose the correct answer from the options given below:

Answer 1

The molecule of benzene ($ \text{C}_6\text{H}_6 $) consists of six carbon atoms arranged in a hexagonal ring. Each carbon atom in benzene is $ sp^2 $-hybridized. Let's break down how many $ sp^2 $ hybrid orbitals are present in benzene:

Each carbon atom in the benzene molecule is $ sp^2 $-hybridized. This means that one 2s orbital and two 2p orbitals of each carbon atom combine to form three $ sp^2 $ hybrid orbitals.
Since benzene has six carbon atoms, and each carbon atom contributes three $ sp^2 $ hybrid orbitals, the total number of $ sp^2 $ hybrid orbitals is calculated as follows:

Total number of $ sp^2 $ hybrid orbitals = Number of carbon atoms × $ sp^2 $ hybrid orbitals per carbon atom

Total number of $ sp^2 $ hybrid orbitals = $ 6 \times 3 = 18 $

Thus, the number of $ sp^2 $ hybrid orbitals in a benzene molecule is 18. Therefore, the correct answer is 18.

Answer 2

The molecule of benzene ($ \text{C}_6\text{H}_6 $) consists of six carbon atoms arranged in a hexagonal ring. Each carbon atom in benzene is $ sp^2 $-hybridized. Let's break down how many $ sp^2 $ hybrid orbitals are present in benzene:

Each carbon atom in the benzene molecule is $ sp^2 $-hybridized. This means that one 2s orbital and two 2p orbitals of each carbon atom combine to form three $ sp^2 $ hybrid orbitals.
Since benzene has six carbon atoms, and each carbon atom contributes three $ sp^2 $ hybrid orbitals, the total number of $ sp^2 $ hybrid orbitals is calculated as follows:

Total number of $ sp^2 $ hybrid orbitals = Number of carbon atoms × $ sp^2 $ hybrid orbitals per carbon atom

Total number of $ sp^2 $ hybrid orbitals = $ 6 \times 3 = 18 $

Thus, the number of $ sp^2 $ hybrid orbitals in a benzene molecule is 18. Therefore, the correct answer is 18.

List - I (Complex)	List - II (Hybridisation)
(A) \([\text{CoF}_6]^{3-}\)	(I) \( d^2 sp^3 \)
(B) \([\text{NiCl}_4]^{2-}\)	(II) \( sp^3 \)
(C) \([\text{Co(NH}_3)_6]^{3+}\)	(III) \( sp^3 d^2 \)
(D) \([\text{Ni(CN}_4]^{2-}\)	(IV) \( dsp^2 \)

The number of $sp^2$ hybrid orbitals in a molecule of benzene is :

The Correct Option is D

Solution and Explanation

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