Step 1: {Central Atom Hybridisation}
In sp\(^3\) d\(^2\) hybridisation, one s, three p, and two d orbitals of the central atom combine to form six hybrid orbitals. This occurs when the central atom is bonded to six other atoms.
Step 2: {Compound Analysis}
In BrF\(_5\), bromine exhibits sp\(^3\) d\(^2\) hybridisation because it is bonded to five fluorine atoms.
In SF\(_6\), sulfur exhibits sp\(^3\) d\(^2\) hybridisation because it is bonded to six fluorine atoms.
In [CrF\(_6\)]\(^{3-}\), chromium exhibits sp\(^3\) d\(^2\) hybridisation due to bonding with six fluoride ions.
In PF\(_5\), phosphorus exhibits sp\(^3\) hybridisation as it is bonded to five fluorine atoms, not six.
Therefore, the correct option is (D).
Match List - I with List - II.
| List - I (Complex) | List - II (Hybridisation) |
|---|---|
| (A) \([\text{CoF}_6]^{3-}\) | (I) \( d^2 sp^3 \) |
| (B) \([\text{NiCl}_4]^{2-}\) | (II) \( sp^3 \) |
| (C) \([\text{Co(NH}_3)_6]^{3+}\) | (III) \( sp^3 d^2 \) |
| (D) \([\text{Ni(CN}_4]^{2-}\) | (IV) \( dsp^2 \) |
Choose the correct answer from the options given below:
Arrange the following in increasing order of solubility product:
\[ {Ca(OH)}_2, {AgBr}, {PbS}, {HgS} \]
Concentrated nitric acid is labelled as 75% by mass. The volume in mL of the solution which contains 30 g of nitric acid is:
Given: Density of nitric acid solution is 1.25 g/mL.
Match List - I with List - II.
List - I (Saccharides) List - II (Glycosidic linkages found)
(A) Sucrose (I) \( \alpha 1 - 4 \)
(B) Maltose (II) \( \alpha 1 - 4 \) and \( \alpha 1 - 6 \)
(C) Lactose (III) \( \alpha 1 - \beta 2 \)
(D) Amylopectin (IV) \( \beta 1 - 4 \)
Choose the correct answer from the options given below: