Hybridisation and geometry of [Ni(CN)$_4$]$^{2-}$ are

Question

Match List - I with List - II.

List - I (Complex)	List - II (Hybridisation)
(A) $[\text{CoF}_6]^{3-}$	(I) $ d^2 sp^3 $
(B) $[\text{NiCl}_4]^{2-}$	(II) $ sp^3 $
(C) $[\text{Co(NH}_3)_6]^{3+}$	(III) $ sp^3 d^2 $
(D) $[\text{Ni(CN}_4]^{2-}$	(IV) $ dsp^2 $

Choose the correct answer from the options given below:

Answer 1

Step 1: Metal Ion Identification
The oxidation state of Nickel in [Ni(CN)$_4$]$^{2-}$ is $ +2 $.
Its electronic configuration is $ 3d^8 4s^0 $.
Step 2: Ligand Influence
CN$^-$ is a strong field ligand, inducing electron pairing within the $ d $-orbitals.
This results in dsp$^2$ hybridization, forming a square planar geometry.
Conclusion: [Ni(CN)$_4$]$^{2-}$ exhibits dsp$^2$ hybridization, resulting in a square planar configuration.

List - I (Complex)	List - II (Hybridisation)
(A) \([\text{CoF}_6]^{3-}\)	(I) \( d^2 sp^3 \)
(B) \([\text{NiCl}_4]^{2-}\)	(II) \( sp^3 \)
(C) \([\text{Co(NH}_3)_6]^{3+}\)	(III) \( sp^3 d^2 \)
(D) \([\text{Ni(CN}_4]^{2-}\)	(IV) \( dsp^2 \)

Hybridisation and geometry of [Ni(CN)$_4$]$^{2-}$ are

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The Correct Option is D

Solution and Explanation

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