Question:medium

The frequency of a closed pipe is $f_1$ if it vibrates with two nodes and is $f_2$ if it vibrates with three nodes. If the difference between the frequencies $f_1$ and $f_2$ is 200 Hz, then the length of the pipe is (Speed of sound in air $=340\,ms^{-1}$)

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For a closed pipe: \[ f=\frac{nv}{4L} \] where \(n=1,3,5,\ldots\). Only odd harmonics are present.
Updated On: Jun 17, 2026
  • $75\text{ cm}$
  • $65\text{ cm}$
  • $85\text{ cm}$
  • $55\text{ cm}$
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The Correct Option is B

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