Question:medium

The following diagram shows a Zener diode as a voltage regulator. The Zener diode is rated at \(V_z = 5\) V and the desired current in load is 5 mA. The unregulated voltage source can supply up to 25 V. Considering the Zener diode can withstand four times of the load current, the value of resistor \(R_s\) (shown in circuit) should be_______ \(\Omega\).

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The series resistor $R_s$ prevents the Zener diode from exceeding its power rating while ensuring sufficient current reaches the load.
Updated On: Mar 29, 2026
  • 100
  • 10
  • 4000
  • 1000
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The Correct Option is D

Solution and Explanation

To determine the value of the resistor \( R_s \) in the Zener diode voltage regulator circuit, we need to consider the regulation requirements and Zener specifications.

Given:

  • Zener Voltage, \( V_z = 5 \, \text{V} \)
  • Load Current, \( I_L = 5 \, \text{mA} \)
  • Unregulated Voltage, \( V_{\text{in}} = 25 \, \text{V} \)
  • Zener Diode can withstand up to four times the load current.

Steps to Calculate \( R_s \):

  1. Determine the maximum Zener current \( I_z \): \(I_z = 4 \times I_L = 4 \times 5 \, \text{mA} = 20 \, \text{mA}\).
  2. Calculate the total current \( I_s \) through \( R_s \): \(I_s = I_L + I_z = 5 \, \text{mA} + 20 \, \text{mA} = 25 \, \text{mA}\).
  3. Apply Kirchhoff’s Voltage Law (KVL) for the loop involving \( R_s \) and the Zener diode: \(V_{\text{in}} = I_s \cdot R_s + V_z\).
  4. Rearrange the formula to solve for \( R_s \): 
    \(R_s = \frac{V_{\text{in}} - V_z}{I_s}\) 
    Substitute the known values: 
    \(R_s = \frac{25 \, \text{V} - 5 \, \text{V}}{25 \, \text{mA}}\) 
    \(R_s = \frac{20 \, \text{V}}{0.025 \, \text{A}} = 800 \, \Omega\).

Given the available options, the most suitable resistor value for \( R_s \) is 1000 Ω, ensuring current is within safe limits and achieving proper voltage regulation.

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