Application of Ohm's Law: \[ V = IR \] With: - Voltage (\( V \)) = 10 V, - Current (\( I \)) = Unknown, - Resistance (\( R \)) = 5 ohms.
Formula rearranged to find \( I \): \[ I = \frac{V}{R} \] Value substitution: \[ I = \frac{10 \, \text{V}}{5 \, \Omega} = 2 \, \text{A} \] Therefore, the resistor carries a current of \( 2.0 \, \text{A} \).