Question

From current electricity, to convert a galvanometer into an ammeter, a shunt is given. Find the resistance of the galvanometer.

• A. \( R_g \)
• B. \( R_s \)
• C. \( R_g + R_s \)
• D. \( \frac{R_g}{R_s} \)

Hint:

For converting a galvanometer into an ammeter, place a shunt in parallel to bypass part of the current.

Answer 1

The Correct Option is C

A galvanometer is transformed into an ammeter by connecting a shunt resistance \( R_s \) in parallel. This parallel connection enables the ammeter to measure substantial currents without risking damage to the galvanometer. The total current entering the circuit divides between the galvanometer and the shunt, with the galvanometer's portion of the current dictated by its resistance.Applying the formula for parallel resistances yields:\[I = \frac{V}{R_g + R_s},\]Here, \( R_g \) denotes the galvanometer's resistance, and \( R_s \) is the shunt resistance. Consequently, the combined resistance of the ammeter configuration is the sum \( R_g + R_s \).