To resolve this issue, we first determine the elements of the set \( A = \{(x, y) : 2x + 3y = 23, \, x, y \in \mathbb{N}\} \). This involves finding pairs \((x, y)\) that satisfy the equation \(2x + 3y = 23\), where \(x\) and \(y\) are natural numbers. We will examine potential \(x\) values and compute their corresponding \(y\) values.
Step 1: As \(x\) and \(y\) are natural numbers, they are positive integers. The smallest possible value for \(x\) is 1.
Step 2: Calculate potential values. We derive \(y\) from the equation:
\(2x + 3y = 23 \Rightarrow 3y = 23 - 2x\). For \(y\) to be an integer, \((23 - 2x)\) must be divisible by 3.
Step 3: Test \(x\) values:
| x | 23 - 2x | Divisible by 3? | y |
|---|---|---|---|
| 1 | 21 | Yes | 7 |
| 2 | 19 | No | - |
| 3 | 17 | No | - |
| 4 | 15 | Yes | 5 |
| 5 | 13 | No | - |
| 6 | 11 | No | - |
| 7 | 9 | Yes | 3 |
| 8 | 7 | No | - |
| 9 | 5 | No | - |
| 10 | 3 | Yes | 1 |
Step 4: The set \( A \) comprises the pairs: \((1,7), (4,5), (7,3), (10,1)\). Therefore, \(A = \{(1, 7), (4, 5), (7, 3), (10, 1)\}\) and \(|A| = 4\).
Step 5: Define set \( B = \{x : (x, y) \in A\}\). Consequently, \( B = \{1, 4, 7, 10\} \). The cardinality of \( B \), denoted \(|B|\), is 4.
Step 6: Compute the number of one-one functions from \( A \) to \( B \). A one-one (bijective) function can exist only if \(|A| = |B|\). The count of such functions equals the number of permutations of \(|B|\), which is \(4!\).
\[4! = 24\]
Conclusion: The total number of one-one functions from \( A \) to \( B \) is 24, which falls within the specified range of 24 to 24.