The correct answer is option (E):
213
Let's break down this problem using the principle of inclusion-exclusion and a strategic approach. We can visualize this using a Venn diagram with three overlapping circles representing TV, AC, and Washing Machine.
1. Define Variables:
* T = Houses with TV = 862
* A = Houses with AC = 783
* W = Houses with Washing Machine = 736
* Only T = Houses with only TV = 95
* Only A = Houses with only AC = 136
* Only W = Houses with only Washing Machine = 88
* T ∩ A ∩ W = Houses with all three equipments = 398
2. Focus on the Target: We want to find the number of houses with only TV and Washing Machine but not AC. This translates to (T ∩ W) - (T ∩ A ∩ W). In other words, we want the intersection of TV and Washing Machine, excluding the houses that also have AC.
3. Using the given Information
* We know how many have all three (T ∩ A ∩ W = 398).
* We know how many have only each.
4. Finding Total number of houses having both TV and Washing Machine
* We can represent the total number of houses having TV as:
* T = Only T + (T ∩ A, but not W) + (T ∩ W, but not A) + (T ∩ A ∩ W)
* 862 = 95 + (T ∩ A, but not W) + (T ∩ W, but not A) + 398
* (T ∩ A, but not W) + (T ∩ W, but not A) = 862 - 95 - 398
* (T ∩ A, but not W) + (T ∩ W, but not A) = 369
* We can represent the total number of houses having Washing Machine as:
* W = Only W + (T ∩ W, but not A) + (A ∩ W, but not T) + (T ∩ A ∩ W)
* 736 = 88 + (T ∩ W, but not A) + (A ∩ W, but not T) + 398
* (T ∩ W, but not A) + (A ∩ W, but not T) = 736 - 88 - 398
* (T ∩ W, but not A) + (A ∩ W, but not T) = 250
* We can represent the total number of houses having AC as:
* A = Only A + (T ∩ A, but not W) + (A ∩ W, but not T) + (T ∩ A ∩ W)
* 783 = 136 + (T ∩ A, but not W) + (A ∩ W, but not T) + 398
* (T ∩ A, but not W) + (A ∩ W, but not T) = 783 - 136 - 398
* (T ∩ A, but not W) + (A ∩ W, but not T) = 249
5. Solving for (T ∩ W, but not A):
* From Step 4, we have (T ∩ A, but not W) + (T ∩ W, but not A) = 369
* From Step 4, we have (T ∩ A, but not W) + (A ∩ W, but not T) = 249
* From Step 4, we have (T ∩ W, but not A) + (A ∩ W, but not T) = 250
* Let's find the value of (T ∩ A, but not W)
* (T ∩ A, but not W) = 369 - (T ∩ W, but not A)
* (T ∩ A, but not W) = 249 - (A ∩ W, but not T)
* Let's find the value of (A ∩ W, but not T)
* (A ∩ W, but not T) = 250 - (T ∩ W, but not A)
* (A ∩ W, but not T) = 249 - (T ∩ A, but not W)
* 249 - (T ∩ A, but not W) = 250 - (T ∩ W, but not A)
* 249 - [369 - (T ∩ W, but not A)] = 250 - (T ∩ W, but not A)
* 249 - 369 + (T ∩ W, but not A) = 250 - (T ∩ W, but not A)
* -120 + (T ∩ W, but not A) = 250 - (T ∩ W, but not A)
* 2 * (T ∩ W, but not A) = 370
* (T ∩ W, but not A) = 185
* Therefore, the number of houses having only TV and washing machine but not AC is 185.
* Now, let's find the number of houses with TV and AC but not Washing Machine
* (T ∩ A, but not W) = 369 - 185 = 184
* Now, let's find the number of houses with AC and Washing Machine but not TV
* (A ∩ W, but not T) = 250 - 185 = 65
6. Find the final answer: The number of houses having only TV and Washing Machine but not AC is 185.
Therefore, the correct answer is 185.