Question:medium

An electronic company conducts a survey of 1500 houses for their products. The survey suggested that 862 houses own TV, 783 houses has AC and 736 houses has washing machine. There were 95 houses having only TV, 136 houses having only AC and 88 houses having only washing machine. There were 398 houses having all the three equipments. How many houses have only TV and washing machine but not AC?

Updated On: Jan 13, 2026
  • 65
  • 119
  • 184
  • 185
  • 213
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The Correct Option is

Solution and Explanation

The correct answer is option (E):
213

Let's break down this problem using the principle of inclusion-exclusion and a strategic approach. We can visualize this using a Venn diagram with three overlapping circles representing TV, AC, and Washing Machine.

1. Define Variables:
* T = Houses with TV = 862
* A = Houses with AC = 783
* W = Houses with Washing Machine = 736
* Only T = Houses with only TV = 95
* Only A = Houses with only AC = 136
* Only W = Houses with only Washing Machine = 88
* T ∩ A ∩ W = Houses with all three equipments = 398

2. Focus on the Target: We want to find the number of houses with only TV and Washing Machine but not AC. This translates to (T ∩ W) - (T ∩ A ∩ W). In other words, we want the intersection of TV and Washing Machine, excluding the houses that also have AC.

3. Using the given Information

* We know how many have all three (T ∩ A ∩ W = 398).
* We know how many have only each.

4. Finding Total number of houses having both TV and Washing Machine

* We can represent the total number of houses having TV as:
* T = Only T + (T ∩ A, but not W) + (T ∩ W, but not A) + (T ∩ A ∩ W)
* 862 = 95 + (T ∩ A, but not W) + (T ∩ W, but not A) + 398
* (T ∩ A, but not W) + (T ∩ W, but not A) = 862 - 95 - 398
* (T ∩ A, but not W) + (T ∩ W, but not A) = 369

* We can represent the total number of houses having Washing Machine as:
* W = Only W + (T ∩ W, but not A) + (A ∩ W, but not T) + (T ∩ A ∩ W)
* 736 = 88 + (T ∩ W, but not A) + (A ∩ W, but not T) + 398
* (T ∩ W, but not A) + (A ∩ W, but not T) = 736 - 88 - 398
* (T ∩ W, but not A) + (A ∩ W, but not T) = 250

* We can represent the total number of houses having AC as:
* A = Only A + (T ∩ A, but not W) + (A ∩ W, but not T) + (T ∩ A ∩ W)
* 783 = 136 + (T ∩ A, but not W) + (A ∩ W, but not T) + 398
* (T ∩ A, but not W) + (A ∩ W, but not T) = 783 - 136 - 398
* (T ∩ A, but not W) + (A ∩ W, but not T) = 249

5. Solving for (T ∩ W, but not A):
* From Step 4, we have (T ∩ A, but not W) + (T ∩ W, but not A) = 369
* From Step 4, we have (T ∩ A, but not W) + (A ∩ W, but not T) = 249
* From Step 4, we have (T ∩ W, but not A) + (A ∩ W, but not T) = 250

* Let's find the value of (T ∩ A, but not W)
* (T ∩ A, but not W) = 369 - (T ∩ W, but not A)
* (T ∩ A, but not W) = 249 - (A ∩ W, but not T)

* Let's find the value of (A ∩ W, but not T)
* (A ∩ W, but not T) = 250 - (T ∩ W, but not A)
* (A ∩ W, but not T) = 249 - (T ∩ A, but not W)

* 249 - (T ∩ A, but not W) = 250 - (T ∩ W, but not A)
* 249 - [369 - (T ∩ W, but not A)] = 250 - (T ∩ W, but not A)
* 249 - 369 + (T ∩ W, but not A) = 250 - (T ∩ W, but not A)
* -120 + (T ∩ W, but not A) = 250 - (T ∩ W, but not A)
* 2 * (T ∩ W, but not A) = 370
* (T ∩ W, but not A) = 185

* Therefore, the number of houses having only TV and washing machine but not AC is 185.

* Now, let's find the number of houses with TV and AC but not Washing Machine
* (T ∩ A, but not W) = 369 - 185 = 184

* Now, let's find the number of houses with AC and Washing Machine but not TV
* (A ∩ W, but not T) = 250 - 185 = 65

6. Find the final answer: The number of houses having only TV and Washing Machine but not AC is 185.

Therefore, the correct answer is 185.
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