To determine the value of α where the gravitational acceleration at height h above Earth's surface equals the gravitational acceleration at a depth αh below the surface, we proceed with the following analysis:
- The acceleration due to gravity at height h is given by:
\( g_h = g_0 \left(1 - \frac{2h}{R_e}\right) \) - At a depth d, the gravity becomes:
\( g_d = g_0 \left(1 - \frac{d}{R_e}\right) \) - According to the problem, these accelerations are equal, i.e.,
\(\left(1 - \frac{2h}{R_e}\right) = \left(1 - \frac{\alpha h}{R_e}\right) \) - Solving for α:
- Start by equating the gravitational terms:
\( 1 - \frac{2h}{R_e} = 1 - \frac{\alpha h}{R_e} \) - Cancel out the common terms and rearrange:
\( \frac{2h}{R_e} = \frac{\alpha h}{R_e} \) - Since h/Re is common, we simplify:
\( 2 = \alpha \)
The calculated value of α is 2, matching the specified range of 2 to 2, thereby confirming the solution is accurate.