Question:medium

solid sphere is rolling purely with speed v on horizontal surface. It rolls up an incline surface and stops at height h. Then height h is [g is the acceleration due to gravity]:

Updated On: Mar 27, 2026
  • \(\frac{3 v^2}{10} g\)
  • \(\frac{7 v^2}{10} g\)
  • \(\frac{5v^2}{7} g\)
  • \(\frac{7v^2}{5} g\)
Show Solution

The Correct Option is B

Solution and Explanation

Option (B) is correct: \( \frac{7 v^2}{10} g \)

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