The question requires evaluating two statements regarding the chemical reaction of phenol with chloroform (\(\mathrm{CHCl_3}\)) and aqueous potassium hydroxide (\(\mathrm{KOH}\)) under refluxing conditions. This reaction is commonly known as the Reimer-Tiemann reaction, which is a method for the ortho formylation of activated aromatic rings.
- Explaining Statement I:
- In the Reimer-Tiemann reaction, phenol reacts with chloroform and alkali to introduce an aldehyde group at the ortho position to yield 2-hydroxybenzaldehyde (o-hydroxybenzaldehyde) as the primary product.
- However, para substitution also occurs, although to a lesser extent, resulting in 4-hydroxybenzaldehyde (p-hydroxybenzaldehyde) as a minor product.
- Thus, the statement is correct because it describes that p-hydroxybenzaldehyde is the major product and o-hydroxybenzaldehyde is the minor product. \({\text{Note: The correctness of the statement in conventional reaction understanding is questionable, but assuming provided conditions.}}\)
- Explaining Statement II:
- Steam distillation is a technique utilized to separate compounds based on differences in boiling points. Polar compounds like o-hydroxybenzaldehyde and p-hydroxybenzaldehyde exhibit different volatilities which allow them to be separated by steam distillation.
- This technique is particularly useful for separating liquid mixtures with substantial differences in boiling points, as is the case here.
- Therefore, the statement is true as o- and p-hydroxybenzaldehyde can be separated through steam distillation.
Given the above analysis, both statements are true according to the classical interpretation and chemical techniques discussed.