Question:medium
Given below are two statements:
Statement I: Propene on treatment with diborane gives an addition product with the formula \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\).
Statement II: Oxidation of \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\) with hydrogen peroxide in presence of NaOH gives propan-2-ol.
In the light of the above statements, choose the most appropriate answer from the options given below:
Given below are two statements:
Statement I: Propene on treatment with diborane gives an addition product with the formula \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\).
Statement II: Oxidation of \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\) with hydrogen peroxide in presence of NaOH gives propan-2-ol.
In the light of the above statements, choose the most appropriate answer from the options given below:
Statement I: Propene on treatment with diborane gives an addition product with the formula \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\).
Statement II: Oxidation of \(((\text{CH}_3)_2 - \text{CH}_3\text{B})\) with hydrogen peroxide in presence of NaOH gives propan-2-ol.
In the light of the above statements, choose the most appropriate answer from the options given below:
Updated On: Feb 11, 2026
- Statement I is correct but Statement II is incorrect
- Statement I is incorrect but Statement II is correct
- Both Statement I and Statement II are correct
- Both Statement I and Statement II are incorrect
Show Solution
The Correct Option is B
Solution and Explanation
Statement I is incorrect. The reaction of propene with diborane (B2H6) yields a trialkyl borane, specifically (CH3)2CH-B. Subsequent oxidation with hydrogen peroxide in NaOH produces propan-2-ol. The formula presented in Statement I does not represent the correct addition product; the initial addition product is a trialkyl borane.
Statement II is correct. Propan-2-ol is formed through the oxidation of the trialkyl borane using H2O2 in NaOH. This process is known as the hydroboration-oxidation reaction.
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