Question

Find the value of $ \log_2 32 $.

• A. \( 5 \)
• B. \( 6 \)
• C. \( 4 \)
• D. \( 3 \)

Hint:

Remember: When solving logarithmic equations, express the number as a power of the same base to easily find the solution.

Answer 1

The Correct Option is A

Step 1: Recall the logarithmic identity
We need to determine the value of \( \log_2 32 \). Remember that \( \log_b x = y \) is equivalent to \( b^y = x \). Here, \( \log_2 32 = y \) implies \( 2^y = 32 \).
Step 2: Express 32 as a power of 2
We know that:\[32 = 2^5\]Substituting this into the equation yields:\[2^y = 2^5\]
Step 3: Solve for \( y \)
With identical bases, we can equate the exponents:\[y = 5\]
Answer:
Consequently, \( \log_2 32 = 5 \). The correct option is (1).