Step 1: Recall the logarithmic identity Determine the value of \( \log_2 32 \). The identity \( \log_b x = y \) is equivalent to \( b^y = x \). For \( \log_2 32 = y \), this means \( 2^y = 32 \). Step 2: Express 32 as a power of 2 Recognize that:\[32 = 2^5\]The equation transforms to:\[2^y = 2^5\]Step 3: Solve for \( y \) Equate the exponents as the bases are identical:\[y = 5\]Answer: Consequently, \( \log_2 32 = 5 \). The correct option is (1).