Let's solve this by setting up coordinates instead of the median-length formula, which makes it obvious why both pieces of information are needed together.
Place the right angle at the origin: $B=(0,0)$, $A=(c,0)$ on one leg, and $C=(0,a)$ on the other leg, where $c=AB$ and $a=BC$.
Using Statement (A) alone: D being the midpoint of BC gives $D=(0, a/2)$, and E being the midpoint of AB gives $E=(c/2, 0)$. This is purely a statement about *where* D and E sit; it says nothing about the actual size of the triangle, so a, c, and hence AC, are completely unknown. Not sufficient.
Using Statement (B) alone: we are told two segment lengths, AD = 7 and CE = 5, but without knowing where D and E are located on their sides, these numbers cannot be tied to a and c in any single way. Not sufficient.
Using both together: with $D=(0,a/2)$ and $A=(c,0)$,
$$AD = \sqrt{c^2 + (a/2)^2} = 7 \implies c^2 + \frac{a^2}{4} = 49$$With $E=(c/2,0)$ and $C=(0,a)$,
$$CE = \sqrt{a^2 + (c/2)^2} = 5 \implies a^2 + \frac{c^2}{4} = 25$$Adding these two equations:
$$\left(a^2+c^2\right)\left(1+\frac14\right) = 74 \implies a^2+c^2 = \frac{296}{5}$$Since $AC=\sqrt{a^2+c^2}$ (AC is the hypotenuse, running from $A=(c,0)$ to $C=(0,a)$), we get a single fixed value:
$$AC = \sqrt{\frac{296}{5}} = \frac{2\sqrt{370}}{5} \approx 7.69$$Let's summarize:
So the two statements together are sufficient, but neither one alone is.
Fill in the blanks using the correct word given in the brackets :
(i) All circles are __________. (congruent, similar)
(ii) All squares are __________. (similar, congruent)
(iii) All __________ triangles are similar. (isosceles, equilateral)
(iv) Two polygons of the same number of sides are similar, if (a) their corresponding angles are __________ and (b) their corresponding sides are __________. (equal, proportional)


