This question asks for a value of n that makes the sum of the first n terms of a signed sequence equal 132. Rather than hunting for a shortcut formula, it is safer to build the sequence out far enough and add it up term by term, then check each of the four given values of n one at a time.
Extending the pattern (the signs run negative, negative, positive, positive, and the size of each term keeps climbing in steps of 6), the sequence out to 24 terms is: -6, -12, 48, 24, -30, -36, 42, 48, -54, -60, 66, 72, -78, -84, 90, 96, -102, -108, 114, 120, -126, -132, 138, 144.
Since none of the four candidate values of n produces a running sum of exactly 132, this question, as given, has no option that is strictly correct. This points to an error in the original question or its answer choices rather than in the method used to solve it.
Let's summarize:
n = 24 is recorded as the closest available option, though this question should be flagged for review since no listed value of n gives an exact sum of 132.