A wire of length \(1.2\,\text{m}\) is subjected to a tension of \(240\,\text{N}\). If the frequencies of two successive modes of vibration of the wire are \(200\,\text{Hz}\) and \(250\,\text{Hz}\), then the mass of the wire is
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For a stretched string,
\[
\boxed{
f_n=\frac{n}{2L}\sqrt{\frac{T}{\mu}}.
}
\]
The difference between two successive frequencies is
\[
\boxed{
f_{n+1}-f_n=\frac{1}{2L}\sqrt{\frac{T}{\mu}}.
}
\]