Question:medium

A source producing sound of frequency \(990\) Hz and an observer are initially at rest. If both the source and observer start moving simultaneously towards each other with accelerations \(2\ \mathrm{ms^{-2}}\) and \(4\ \mathrm{ms^{-2}}\) respectively, then the frequency of sound heard by the observer at a time \(t=5\) s is \[ (\text{Speed of sound in air}=340\ \mathrm{ms^{-1}}) \]

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For Doppler effect when the source and observer move towards each other, \[ \boxed{ f' = f \left( \frac{v+v_o}{v-v_s} \right). } \] If the bodies start from rest with uniform acceleration, \[ \boxed{v=at.} \]
Updated On: Jul 18, 2026
  • \(960\) Hz
  • \(1080\) Hz
  • \(1050\) Hz
  • \(900\) Hz
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The Correct Option is B

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