Question

A particle is having uniform acceleration. If its displacement from t to \((t + 1)\) second is \(120 \) \(m\) and change in velocity is \(50 \;m/s\). Find its displacement (in m) in \((t + 2)^{th}\) second

Answer 1

\(\text{The displacement is calculated as follows:}\)

\(a=50\;m/s^2\)

\(120=u+\frac{a}{2}(2(t+1)-1)\)

\(u=120-25(2t+1)\)

\(s'=u+\frac{a}{2}(2(t+2)-1)\)

\(=u+25(2t+3)\)

The Correct Answer is : \(170\)