Question:medium
A compound microscope has an objective of focal length $1.25\,\mathrm{cm}$ and an eyepiece of focal length $5\,\mathrm{cm}$ separated by a distance of $7.5\,\mathrm{cm}$. The total magnification produced by the microscope when the final image forms at infinity is
A compound microscope has an objective of focal length $1.25\,\mathrm{cm}$ and an eyepiece of focal length $5\,\mathrm{cm}$ separated by a distance of $7.5\,\mathrm{cm}$. The total magnification produced by the microscope when the final image forms at infinity is
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Microscope Magnification (Infinity): $M = \frac{L}{f_o} \frac{D}{f_e}$.
Microscope Magnification (Near Point): $M = \frac{L}{f_o} (1 + \frac{D}{f_e})$.
Updated On: Mar 26, 2026
- 6.25
- 30
- 120
- 72.5
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The Correct Option is B
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