The given set of reactions involves the conversion of alcohols to bromoalkanes using HBr under heat. The reactions are as follows:
The first reaction is the conversion of benzyl alcohol (\(\text{C}_6\text{H}_5\text{CH}_2\text{OH}\)) to benzyl bromide (\(\text{C}_6\text{H}_5\text{CH}_2\text{Br}\)). In the presence of HBr and heat, the hydroxyl group (-OH) is replaced by a bromine atom to form compound A.
The second reaction involves the conversion of p-methoxyphenol to 4-bromoanisole. The presence of the methoxy group (-OCH3) directs the bromination to the para position of the aromatic ring, leading to the formation of compound B.
In both reactions, the hydroxyl group is substituted by a bromine atom in the presence of HBr and elevated temperature.
Therefore, the correct identification of the compounds A and B formed in the reactions is as follows:
In summary, compound A is benzyl bromide, and compound B is 4-bromoanisole, consistent with the provided reactions and the correct answer.
Was this answer helpful?
1
Top Questions on introduction to organic chemistry
