List of top Physics Questions on P-N Junction

Consider the following statements A and B and identify the correct answer:

A. For a solar-cell, the I-V characteristics lies in the IV quadrant of the given graph.
B. In a reverse biased pn junction diode, the current measured in (µA), is due to majority charge carriers.

When a potential difference V is applied across a wire of resistance R, it dissipates energy at a rate W. If the wire is cut into two halves and these halves are connected mutually parallel across the same supply, the same supply, the energy dissipation rate will become:

Given below are two statements ; one is labelled as Assertion $A$ and the other is labelled as Reason $R$

Assertion A: Photodiodes are used in forward bias usually for measuring the light intensity

Reason R: For a p-n junction diode at applied voltage $V$ the current in the forward bias is more than the current in the reverse bias for $\left|V_2\right|>\pm V \geq\left|V_0\right|$ where $V_0$ is the threshold voltage and $V _2$ is the breakdown voltage

In the light of the above statements, choose the correct answer from the options given below

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: Diffusion current in a p-n junction is greater than the drift current in magnitude if the junction is forward biased.
Reason R: Diffusion current in a p-n junction is from the n-side to the p-side if the junction is forward biased.
In the light of the above statements, choose the most appropriate answer from the options given below

The photodiode is used to detect the optical signals. These diodes are preferably operated in reverse biased mode because:

In the given circuit the input voltage V_in is shown in figure. The cut-in voltage of p–n junction diode
(D₁ or D₂) is 0.6 V. Which of the following output voltage (V₀) waveform across the diode is correct?

In the circuit shown below, maximum Zener diode current will be ________ mA.

In a p-n junction diode, change in temperature due to heating

A set of ‘n’ equal resistors, of value ‘R’ each, are connected in series to a battery of emf ‘E’ and internal resistance ‘R’. The current drawn is I. Now, the ‘n’ resistors are connected in parallel to the same battery. Then the current drawn from battery becomes 10 I. The value of ‘n’ is

The current gain of a common emitter amplifier is $69$ . If the emitter current is $7.0 \,mA$, collector current is :

The current in the circuit shown in the figure, considering ideal diode is