Question:medium
In the following electrical circuit, the reading in the milliammeter is
(Take knee voltage of silicon diode \(= 0.7\) V)
In the following electrical circuit, the reading in the milliammeter is
(Take knee voltage of silicon diode \(= 0.7\) V)
(Take knee voltage of silicon diode \(= 0.7\) V)
Show Hint
The diode is forward biased, so subtract the knee voltage from the battery voltage before applying Ohm's law.
Updated On: Oct 1, 2026
- \(25.5\) mA
- \(21.5\) mA
- \(18.5\) mA
- \(15.8\) mA
Show Solution
The Correct Option is B
Solution and Explanation
Step 1: Series loop
The same current flows through the diode, resistor and meter. Kirchhoff's voltage law gives $5 = 0.7 + 200I$.
Step 2: Solve
$200I = 4.3$, so $I = 0.0215$ A.
Step 3: Convert
$0.0215\ \text{A} = 21.5$ mA.
Step 4: Rule out
If the knee voltage were ignored, $I = 25$ mA, and options 18.5 mA and 15.8 mA would need drops of $1.3$ V and $1.84$ V.
Final Answer:
The reading is 21.5 mA. This is option (B). \[ \boxed{\text{(B) }21.5\ \text{mA}} \]
The same current flows through the diode, resistor and meter. Kirchhoff's voltage law gives $5 = 0.7 + 200I$.
Step 2: Solve
$200I = 4.3$, so $I = 0.0215$ A.
Step 3: Convert
$0.0215\ \text{A} = 21.5$ mA.
Step 4: Rule out
If the knee voltage were ignored, $I = 25$ mA, and options 18.5 mA and 15.8 mA would need drops of $1.3$ V and $1.84$ V.
Final Answer:
The reading is 21.5 mA. This is option (B). \[ \boxed{\text{(B) }21.5\ \text{mA}} \]
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