Question:medium
In the circuit shown in figure all the three diodes D1, D2, D3 have forward resistance \(50 \Omega\) each and infinite backward resistance. If the battery voltage is 5V, the current through \(100 \Omega\) resistance is
In the circuit shown in figure all the three diodes D1, D2, D3 have forward resistance \(50 \Omega\) each and infinite backward resistance. If the battery voltage is 5V, the current through \(100 \Omega\) resistance is
Show Hint
Find which diodes conduct, then combine the resistances.
Updated On: Oct 1, 2026
- \(60\) mA
- \(30\) mA
- \(20\) mA
- \(10\) mA
Show Solution
The Correct Option is B
Solution and Explanation
Step 1: Remove the blocked diode
D3 is reversed, so its branch carries no current.
Step 2: Compute with conductances
Branch conductances: $\dfrac1{200}+\dfrac1{100}=\dfrac{3}{200}$ S, so the parallel part is $\dfrac{200}{3}\ \Omega$. Total resistance $166.7\ \Omega$ and $I=\dfrac5{166.7}=30$ mA, option (B).
Final Answer:
The current is 30 mA, option (B). \[ \boxed{30\ \text{mA}} \]
D3 is reversed, so its branch carries no current.
Step 2: Compute with conductances
Branch conductances: $\dfrac1{200}+\dfrac1{100}=\dfrac{3}{200}$ S, so the parallel part is $\dfrac{200}{3}\ \Omega$. Total resistance $166.7\ \Omega$ and $I=\dfrac5{166.7}=30$ mA, option (B).
Final Answer:
The current is 30 mA, option (B). \[ \boxed{30\ \text{mA}} \]
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