Question:medium

\(\sqrt{x + 6\sqrt{2}} - \sqrt{x - 6\sqrt{2}} = 2\sqrt{2}.\)
Find \( x \).

Updated On: Nov 24, 2025
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Correct Answer: 11

Solution and Explanation

Step 1: Define variables and square the given equation.

Let \(a = \sqrt{x + 6\sqrt{2}}\) and \(b = \sqrt{x - 6\sqrt{2}}\). The equation becomes:

\(a - b = 2\sqrt{2}. \quad \text{(1)}\)

Squaring both sides yields:

\((a - b)^2 = (2\sqrt{2})^2.

\(a^2 - 2ab + b^2 = 8. \quad \text{(2)}\)

Step 2: Express \( a^2 \) and \( b^2 \) in terms of \( x \).

From their definitions:

\(a^2 = x + 6\sqrt{2}\) and \(b^2 = x - 6\sqrt{2}\).

Adding them:

\(a^2 + b^2 = (x + 6\sqrt{2}) + (x - 6\sqrt{2}) = 2x. \quad \text{(3)}\)

Subtracting them:

\(a^2 - b^2 = (x + 6\sqrt{2}) - (x - 6\sqrt{2}) = 12\sqrt{2}. \quad \text{(4)}\)

Step 3: Substitute into Equation (2).

Equation (2) is \(a^2 + b^2 - 2ab = 8\). Substituting \(a^2 + b^2 = 2x\):

\(2x - 2ab = 8.\)

Solving for \( ab \):

\(ab = \frac{2x - 8}{2} = x - 4. \quad \text{(5)}\)

Step 4: Find \( a + b \) using the difference of squares.

We know \( (a - b)(a + b) = a^2 - b^2 \). Using Equation (1) \(a - b = 2\sqrt{2}\) and Equation (4) \(a^2 - b^2 = 12\sqrt{2}\):

\((2\sqrt{2})(a + b) = 12\sqrt{2}.\)

This simplifies to:

\(a + b = 6. \quad \text{(6)}\)

Step 5: Solve for \( a \) and \( b \).

We have a system of two linear equations:

\(a - b = 2\sqrt{2}\)

\(a + b = 6\)

Adding these equations gives \(2a = 6 + 2\sqrt{2}\), so:

\(a = 3 + \sqrt{2}.\)

Subtracting the first equation from the second gives \(2b = 6 - 2\sqrt{2}\), so:

\(b = 3 - \sqrt{2}.\)

Step 6: Find \( x \) using \( a^2 = x + 6\sqrt{2} \).

Substitute \( a = 3 + \sqrt{2} \) into \( a^2 = x + 6\sqrt{2} \):

\((3 + \sqrt{2})^2 = x + 6\sqrt{2}.\)

Expanding the left side:

\(9 + 6\sqrt{2} + 2 = 11 + 6\sqrt{2}.\)

So, the equation becomes:

\(11 + 6\sqrt{2} = x + 6\sqrt{2}.\)

Solving for \( x \):

\(x = 11.\)

Final Answer:

\(x = 11.\)

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