Understanding the Concept:
Iodoform test is given by compounds containing:
\[
-COCH_3 \quad \text{(methyl ketone)} \quad \text{or} \quad CH_3CH(OH)-
\]
Step 1: Understand reaction.
\[
RCOCH_3 + I_2 + NaOH \rightarrow CHI_3 \downarrow + \text{other products}
\]
Yellow precipitate of iodoform confirms the test.
Step 2: Analyze each option.
(A) Propanal:
Structure: \(CH_3CH_2CHO\)
Does not contain \(CH_3CO-\) group → no reaction.
(B) Ethanal:
Structure: \(CH_3CHO\)
This behaves like methyl ketone in haloform reaction → gives iodoform.
(C) Benzophenone:
No methyl ketone group → no reaction.
(D) Benzaldehyde:
Aromatic aldehyde → no iodoform test.
(E) Phenol:
No carbonyl → no reaction.
Final Final Answer:
\[
\boxed{\text{Ethanal gives iodoform test}}
\]