Freezing point depression is proportional to the number of dissolved particles. The van't Hoff factor, denoted by \(i\), quantifies the number of particles a solute dissociates into. For 1 M solutions:
- Glucose, a non-dissociating solute, has \(i = 1\).
- NaCl dissociates into two ions, resulting in \(i = 2\).
- AlCl3 dissociates into four ions, giving \(i = 4\).
- MgCl2 dissociates into three ions, with \(i = 3\).
Consequently, AlCl3 will induce the most significant freezing point depression due to its highest ion production.