The correct order of boiling points of the given aqueous solutions is

Question

P and Q combine to form two compounds PQ₂ and PQ₃. If 1 g of PQ₂ is dissolved in 51 g of benzene, the depression of freezing point becomes 0.8°C. On the other hand, if 1 g of PQ₃ is dissolved in 51 g of benzene, the depression of freezing point becomes 0.625°C. The atomic mass of P and Q are (K_f of benzene = 5.1 K·kg/mol):

Answer 1

Boiling point elevation is a colligative property determined by the quantity of solute particles in the solution:

KNO₃: A strong electrolyte, it breaks down into 2 ions (K⁺ and NO⁻₃).
NaCl: A strong electrolyte, it breaks down into 2 ions (Na⁺ and Cl⁻).
CH₃COOH: A weak electrolyte, it partially breaks down into CH₃COO⁻ and H⁺ ions.
Sucrose: A non-electrolyte; it does not break down.

23

Because strong electrolytes like KNO₃ and NaCl create more particles in solution than weak electrolytes like CH₃COOH and non-electrolytes like sucrose, the order of boiling points is: 1 N KNO₃ = 1 N NaCl>1 N CH₃COOH>1 N sucrose.

The correct order of boiling points of the given aqueous solutions is

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The Correct Option is B

Solution and Explanation

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