Question

Which of the following molecules represents the order of hybridisation sp² , sp² , sp, sp from left to right atoms ?

• A. HC ≡ C – C ≡ CH
• B. CH₂ = CH – CH = CH₂
• C. CH₂ = CH – C ≡ CH
• D. CH₃ – CH = CH – CH₃

Answer 1

The Correct Option is C

To determine the hybridization of the given molecule \( \mathrm{CH_2 = CH - C \equiv CH} \), we need to analyze the hybridization of each carbon atom in the molecule from left to right.

1. First carbon atom (CH₂=): The first carbon is doubly bonded to another carbon as in C=C. In such compounds, the carbon is sp² hybridized.
   Hybridization Formula: For sp² hybridization, the steric number should be 3 (2 sigma bonds + 1 π bond).
2. Second carbon atom (CH=): This is the middle carbon atom involved in a double bond with one other carbon (CH₂=CH-), hence also sp² hybridized.
3. Third carbon atom (-C≡): In triple-bonded carbon such as in -C≡C-, carbon is sp hybridized.
   Hybridization Formula: For sp hybridization, the steric number should be 2 (2 sigma bonds).
4. Fourth carbon atom (≡CH): This terminal carbon is part of a triple bond as well (C≡CH), thus sp hybridized.

Therefore, the hybridization order for each carbon atom from left to right in this molecule is sp², sp², sp, sp.

Conclusion: The correct molecule representing the hybridization order sp², sp², sp, sp is CH₂=CH–C≡CH. The structure and bonds confirm the hybridization order.