Question:medium

Which compound does not show an iodoform test?

Show Hint

Check which compound lacks a methyl group directly attached to a carbonyl.
Updated On: Jul 3, 2026
  • Acetaldehyde
  • Acetone
  • Propanal
  • Acetophenone
Show Solution

The Correct Option is C

Solution and Explanation

Method: mechanism check. The iodoform reaction needs a methyl group directly bonded to carbonyl carbon to form the CI3 leaving group. Propanal's alpha hydrogens belong to a CH2 group, not CH3, so the trihalomethyl leaving group can never form.
\[\boxed{\text{Propanal}}\]
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