Question:medium

Select the correct options:
Statement 1: Benzene sulphonyl chloride reacts with 1°, 2° and 3° amines.
Statement 2: All products of the reaction above are soluble in NaOH.

Updated On: Mar 19, 2026
  • Statement 1 is true and statement 2 is false.
  • Statement 1 is false and statement 2 is true.
  • Statement 1 and statement 2, both are true.
  • Statement 1 and statement 2, both are false.
Show Solution

The Correct Option is D

Solution and Explanation

To determine the correctness of the statements, let's analyze each statement individually based on chemical reactions involving benzene sulphonyl chloride (BSC) and amines.

Statement 1: Benzene sulphonyl chloride reacts with 1°, 2°, and 3° amines.

When benzene sulphonyl chloride reacts with different types of amines, the reactions are as follows:

  • 1° Amines (primary amines): These react with BSC to form sulphonamides, which are water-insoluble but soluble in alkali due to the acidic hydrogen in the sulphonamide group.
  • 2° Amines (secondary amines): These also react with BSC to form sulphonamides.
  • 3° Amines (tertiary amines): Tertiary amines do not form sulphonamides upon reaction with BSC because they lack a hydrogen atom that can be replaced by the sulphonyl group, making this reaction impossible.

Therefore, statement 1 is false because benzene sulphonyl chloride does not react with tertiary amines.

Statement 2: All products of the reaction above are soluble in NaOH.

The products of the reaction of BSC with primary and secondary amines are sulphonamides. Sulphonamides formed from primary amines are soluble in NaOH due to the presence of an acidic hydrogen. However, sulfonamides from secondary amines generally lack acidic hydrogens and, therefore, are not soluble in NaOH.

Thus, statement 2 is also false because not all products are soluble in NaOH.

Conclusion:

Both statements 1 and 2 are false, which corresponds to the correct option: "Statement 1 and statement 2, both are false."

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